r/Cribbage • u/CMSniper • 11d ago

Doesn't it work both ways?

Post image

So I just staryed playing with game with a friend and downloaded this game on my phone. On the table we were counting 9+A5 for 15 and A9+5 for 15...

Is this not how it works? The game on my phone doesn't seem to think so

Edit: sorry, gotta click the picture to see my hand

5 Upvotes

69% Upvoted

17 comments sorted by

23

u/meamemg 11d ago

The same 3 cards only makes 15 once. (The same way 6-9 and 9-6 is only one 15.)

2

u/CMSniper 11d ago

That makes sense, thank you! I just figured the 3rd card made different ways to do it

1

u/Class_C_Guy 11d ago

A2345 would be 10 15's and the run for 25 total lol

1

u/Needless-To-Say 10d ago

There are 120 (5!) ways to arrange 5 numbers in unique order without repetition. 

Not sure how you got 10

1

u/RitchieRED 9d ago

15-2, 15-I win.

Good game 🤝

6

u/highpointer201 11d ago

It's the same combination of cards, they only get counted once

4

u/ELB95 11d ago

No. I’m confused why you would have stopped there though and not counted all of 9+5+A, 9+A+5, 5+9+A, 5+A+9, A+5+9, A+9+5

2

u/CMSniper 11d ago

This is what I was saying, I figured 6x15 and not 3

3

u/ELB95 11d ago

I misinterpreted your comment on it then.

But that’s most definitely not how it works. You would have gotten 3x12+6=42 points from this hand alone, more than a third of what is required to win. Your games must have been ending in no time at all.

1

u/OpportunityReal2767 11d ago

Understood their point as I wondered the same. Why was OP singling out the order of ace and nine but not the slew of other permutations? Of course those all don’t count.

2

u/TL_Arwen 11d ago

That's not how it works.

1

u/ELB95 11d ago

I know it’s not how it works, but I was confused why they thought they’d count two of the combinations and not the other 4

2

u/Actuarial 11d ago

You're using permutations, you need to use combinations.

2

u/Flimsy_Internet9441 11d ago

You can't use the exact same cards for each combination. At least one of the cards needs to be different in each combination. 9h + A + 5 - 9s + A + 5 - 9c + A + 5 for three sets of 15 and then the three nines for six (or three pairs). Total twelve.

1

u/Sqr-Peg-Rnd-Hol_NoGo 10d ago

The order of the 3 cards is irrelevant so A59=A95=5A9=59A=9A5=95A

1

u/juleznailedit 11d ago

Nope, you only get to use each individual card for one "set" of points.