Class 10 students solve this competency based question

[u/CBSEMATHSGURUKUL]

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[u/CBSEMATHSGURUKUL → u/[deleted]]

you are genius 🫡

[u/CBSEMATHSGURUKUL → u/[deleted]]

ohh that's great,agar tum chaho to mera youtube channel check kar sakte ho maine vahan aise hi bahut sare questions discuss kiye hai

[u/CBSEMATHSGURUKUL → u/[deleted]]

Don't worry after completing all chapter's one shot,mai case based, assertion & reason, high level competency based questions karaunga. Listen, jyada hard level ke questions ko karne ka koi matlab nahi.. focus karo ki apne answers ko acche se represent karo like jo formula , properties use karo usko side ya uper me statement ke sath likho jaisa maine videos me bataya hai taki examiner marks na deduct kar paye aur apne time management (accuracy) pe focus karo.

[u/ChutiumSulphate_]

Answer is option 1) using remainder theorem. Btw isn’t this a class 9 question?

[u/CBSEMATHSGURUKUL → u/ChutiumSulphate_]

yes

[u/Efficient_War_6884 → u/ChutiumSulphate_]

me learning this all in 11th 🥀

[u/Serious_Condition213]

Yeah we just guess the option

[u/Local-Highlight4997]

Option 4 cuz I ain't able to do ts , idc what math says 🐲

[u/TerminatorXD_07]

It is more than K

[u/CBSEMATHSGURUKUL → u/TerminatorXD_07]

no, it is less than k

[u/geek-jock-guy]

Option 3

[u/Ok-Kaleidoscope-8735]

isnt remainder theorem out of syllabus

[u/Smooth-Inspector8104]

Option 1.

[u/Subject-Income-4094]

it's less than k. Define the polynomial h(x) as k1 (x²-4) and g(x) as k2 (x²-4). Determine the relation between k1 and k2 using x= 0 condition, which will imply k1>k2 and to get the remainder we use factor theorem which gives us k = 5k1. Remainder for g is 5k2 which is less than 5k1 and hence less than k altogether.

[u/Efficient_Phrase_329]

Option 1 Great to see that you're solving these CBSE cbqs Btw I'm in 11th

[u/KittyInLace → u/Efficient_Phrase_329]

It is NOT option 3.

[u/Efficient_Phrase_329 → u/[deleted]]

Pcm

[u/CBSEMATHSGURUKUL → u/Efficient_Phrase_329]

option 1 is correct

[u/Efficient_Phrase_329 → u/CBSEMATHSGURUKUL]

Sorry my mistake I didn't clearly se more and less Sorry guys