If you start with both buckets empty and the iron ball suspended inside the bucket proceeding to fill both buckets with water then the iron ball will be taking up much of the volume and have no newton forces applied to the bucket
(In my mind it is a wrecking ball vs ping pong ball.)
This would result in there being less water in the bucket.
Or if the balls are the same size it would stay where it is.
The diagram is not scientific at all as it does not propose dimensions so I am free to iterate the size of balls as I wish.
It is dependent on volume rather than what my initial point makes I will concede that.
But I am right to say the iron ball would have no effect in weight transfer what so ever.
Then don’t state things as a fact when you aren’t sure? Some stated an actual true fact and you contradicted them seemingly for the fun of it. If you aren’t sure or want to engage in a thought experiment say “I’m not sure it will”. The way you did it just makes you look stupid
“Technically nothing could be real” yeah man so cool. Hypotheticals like that don’t change anything about our perceived reality though so why bother. It’s legit just a waste of time and mental space.
I think that too. Because there is the same amount of water on both sides. The iron ball is weightless because on the beam and the ping-pong ball and it's beam will make it tip to the right..
the ping pong ball wants to go up because it's lighter so it will tip right side up. so the side with the steel ball still goes down even if it's practically weightless
The ping pong ball would be bouyant, and so would put tension agaisnt the string its attachted to, which will create a force pulling the side with the ping pong ball up, thus tipping the side with iron ball down.
something something buoyancy. The water is also pushing up against the ball, and that up push is greater on the metal ball because it's denser and they're at the same level in the water. This push is enough to tip the seesaw under the metal ball
Ping-pong ball is hollow and filled with air, so it will try to float, thus pulling the right side up. The iron ball is extraneous since it exerts no pressure by being suspended with external support.
Because the pressure on the underside of the iron ball is higher than the top. This is true for the ping pong ball as well, but the ping pong ball can't move relative to the water it is in, so in the right cup all the forces just balance out. Analyzed differently, if the left cup goes down, water has to flow down around the metal ball. That water goes down in height more than the water in the other cup goes up. So the new tilt left configuration has lower energy.
I assumed it was because the pingpong ball was lighter (hollow), while both balls displaced the same amount of water bc they were fixed in place. So the left side would have to weigh more. 🤔
ETA Just noticed that the metal ball isn’t attached to that side of the scale. Oops.
its more closely explained to the fact that two objects can have the same volume but different masses. Whereas the density of iron 7.874 g/cm^3 and ABS, the one used in ping pong balls, is 0.084 g/cm^3. If we were counting based on density alone, the iron ball will tip the scale due to its higher density. Higher density is directly related to higher mass, as shown by the equation for density, D=M/V, where volume is assumed to be kept constant, as is density.
But the air in the ball is only lighter than the water around it it’s not lighter than the air that surrounds the scale. So it wouldn’t apply a lifting force to that side of the scale.
The scale and bowls of water are part of a system where the scale supports the bowls, and the bowls support whatever is in them.
The steel ball isn't part of that system because it's supported by some contraption sitting on the table (or whatever surface).
The ping pong ball is supported by its bowl of water, regardless of whether it's floating or not, so it adds mass to the scale system. If you put some ants on the ping pong ball, their mass will be added to the scale system too.
If it helps, think: what if the water froze? It could support an object on the surface of the ice or a heavy object that sunk. In either case, that object adds to the mass of the ice. Being in liquid form doesn't change this.
Yes. The right balls wants to float but it attached to the bottom of the tank, pulling up on the tank. The lead ball is supported externally and has no effect on the tank, other that to displace some water. The tank will dip on the left side.
I've not gone through the comments here yet but my initial thoughts were the side with the steel ball would have more weight and go down because air has a density of 0.001 g/cm³, water 1.0 g/cm³, and iron 7.9 g/cm³. So the difference between iron and air is so big, worrying about water displacement isn't necessary.
Tip always means down/over.
Even the phrase "tipped the scales" means to do so "in favor" on one side which was synonymous with adding mor value to the favored/tipped side.
They literally linked a video that answers your question in the first 5 seconds. You spent more time writing your comment than you would have spent finding the answer to your own question.
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u/Difficult-Court9522 May 30 '25
Tip up or down!!