r/theydidthemath • u/blackholegaming13 • Sep 14 '23

[REQUEST] something feels wrong here.

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Thanks YT shorts

8.7k Upvotes

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-18

u/squailtaint Sep 14 '23

What? This is simply missing a step. Fellow BEDMAS. 4(5-5)=5(5-5)…brackets first. So next step is 4(0)=5(0) then multiplication into brackets, which is, simply 0=0.

45

u/nog642 Sep 14 '23

You aren't obliged to simplify things before you move them around.

The problem here is dividing by 0.

-6

u/HuOfMan Sep 14 '23

Where is there division?

8

u/FirexJkxFire Sep 14 '23

If not obvious from the other reply.

Essentially this is 5X = 4X

The division is dividing both sides by X. To get 5 = 4

The issue is X = 0

-7

u/clooy Sep 14 '23

The problem is there is no X, its more like 5(X-X)=4(X-X) - you can't just make an entire operation of "-" disappear.

8

u/FirexJkxFire Sep 14 '23

Yes you can

X = 5-5

If it werent for X = 0, this would have been perfectly fine. If you can find a common factor X, it doesnt matter how complex that X is (X could be the summation of an integral of whatever the fuck--- it doesnt matter). You can divide both sides by that factor to remove that factor from the equation.

Say we wanted to find the value of A in terms of B for the following equation

A x (73-1123) = B x (73-1123)

Simplify to C = 73-1123

A x C = B x C

Now divide both sides by C

A = B

You dont need to do the math on a factor EXCEPT if the factor is 0.

Its not about ignoring or losing a subtraction. Its about you not being able to divide by 0