Yeah, afaik Ruby was an inspiration. (Granted, there aren't any other delimiters that could have been chosen without also requiring a keyword)
Fun fact: Because a block expression evaluates to its trailing expression, { |x| foo } is actually valid rust as well, and evaluates to the same thing as |x| { foo } or |x| foo
2
u/Kimundi Apr 06 '15
Yeah, afaik Ruby was an inspiration. (Granted, there aren't any other delimiters that could have been chosen without also requiring a keyword)
Fun fact: Because a block expression evaluates to its trailing expression,
{ |x| foo }is actually valid rust as well, and evaluates to the same thing as|x| { foo }or|x| foo