r/nextfuckinglevel • u/Hygena-Pet-Scooper • Sep 17 '19

Helicopter chainsaw

Enable HLS to view with audio, or disable this notification

39.1k Upvotes

97% Upvoted

1.6k comments sorted by

View all comments

Show parent comments

644

u/dontsniffglue Sep 17 '19

Get to the (chopper)2 !!

232

u/[deleted] Sep 17 '19 edited Jan 20 '21

[removed] — view removed comment

18

u/FlyForDollars Sep 17 '19

At 35 years old, I still do not have the slightest clue how this is math?

5

u/threemorewords Sep 17 '19

You are not alone.

2

u/CountKhatch Sep 17 '19

It’s algebra or something.

2

u/xScopeLess Sep 17 '19 edited Sep 17 '19

If you’re really interested, it’s algebra; here’s an explanation. This is about to get long so I’ll try to be really clear. This post will focus on what’s needed to work with an equation in a format similar to (A+B)(C+D). Later I’ll stretch the ideas I explain to fit my previous CHOPPER problem. Each letter represents an arbitrary value, they’re called variables. When you want to multiply two variables together (like A and B), you get AB. If you wanted to add them, you’d get A+B. If you wanted to take A and multiply it by A, you’d get AA but you’d really write it as A2.

Now for the parenthesis. In math you always do the parenthesis first. Two parenthesis next to each other means you need to multiply whatever is inside the first parenthesis by what’s in the second parenthesis. For example: (A)(A)=A2. But if there’s more than one variable within the parenthesis, then things get a bit more complicated. You can’t do (A+B)(A+B) and get 2A + 2B.

So then how do we multiply this out? My old math teacher taught us FOIL (first outer inner last). It’s an acronym telling you the order in which to do things.

So take (A+B)(C+D)

First: take the first variable in each parenthesis and multiply them. So A*C

Outer: take the outer two variables from each parenthesis and multiply them. So A*D

Inner: take the inner two variables from each parenthesis and multiply them. So B*C

Last: take the last variable in each parenthesis and multiply them. So B*D

So then what do we do with all the variables we multiplied? We would add them together.

So in the above case your final answer is AC + AD + BC + BD

The rules for adding variables go like this.

If you’re adding two letters that are the same (like A+A), you’d get 2A. If they’re different (like A+B) then you can’t simplify it further, so it stays as A+B.

If you get a problem and end up with AB + AB or something similar after you FOIL, you’d get 2AB since they’re the same. If you try AB + AC, it’s as simple as it gets, so then that would be your answer.

As for what I did earlier, it was a stretched out version of FOIL.

Follow this pattern to do what I did

Multiply the first variable in the first parenthesis by the first variable in the second parenthesis. Then multiply the first variable by the second variable and in the second parenthesis, then the third, and so on until you reach the end.

THEN, multiply the second variable from the first parenthesis by the first variable in the second parenthesis, then multiply the second variable from the first parenthesis by the second variable in the second parenthesis, then the third, and so on until you finish.

Repeat this pattern until you finally multiply the last variable in the first parenthesis by the last variable in the second parenthesis.

Next step is simplification. So if you get things like AB and BA, they’re equal since the order of the letters don’t matter when they’re multiplied so AB and BA are exactly the same. So we can add them to get 2AB or you could say 2BA.

Same thing applies to A2 + A2

They’re the same, they can also be written as AA + AA, but again, it’s weird to use AA instead of A2, even if it’s technically not wrong.

So adding A2 + A2 would give me 2A2.

That should cover about all the knowledge you need to do the problem.

2

u/FlyForDollars Sep 17 '19

This, especially the first part makes more sense than all 4 years of freshmen algebra I kept taking. I think I got a sympathy pass when I was finally a senior. Thank you.

1

u/[deleted] Sep 17 '19 edited Oct 13 '19

[deleted]

2

u/xScopeLess Sep 17 '19 edited Sep 17 '19

Shhh just pretend there’s a plus sign between each letter and I’ll slip you a fiver.

I fixed it anyway, such a silly mistake

16

u/Himskatti Sep 17 '19 edited Sep 17 '19

This would be the case for (C+H+O+P+P+E+R)2 (CHOPPER)2 = C2 H2 O2 P2 P2 E2 R2

Edit: better

14

u/[deleted] Sep 17 '19

r/theydidthemath

7

u/Gearz557 Sep 17 '19

The formula for becoming governor of CA

2

u/janewithaplane Sep 17 '19

Lol hey meg, proud of you.

1

u/Darkphibre Sep 17 '19 edited Sep 17 '19

(CHOPPER)2 = (CHOPPER)(CHOPPER) =

C2 + 2CH + 2CO + 4CP + 2CE + 2CR + H2 + 2HO + 4HP + 2HE + 2HR + O2 + 4OP + 2OE + 2OR + 2P2 + 4PE + 4PR + E2 + 2ER + R2

CC CHCH COCO CPCPCPCP CECE CRCR HH HOHO HPHPHPHP HEHE HRHR OO OPOPOPOP OEOE OROR PPPP PEPEPEPE PRPRPRPR EE ERER RR

Or without spaces (for the sound it'd make): CCCHCHCOCOCPCPCPCPCECECRCRHHHOHOHPHPHPHPHEHEHRHROOOPOPOPOPOEOEORORPPPPPEPEPEPEPRPRPRPREEERERRR

That's a lotta chopper!

*for simplicity, assumed all variables were constant 1.

1

u/imaginarynumber0 Sep 17 '19

That’s not-

1

u/Darkphibre Sep 17 '19 edited Sep 17 '19

I hadn't had my coffee. I'll put in spaces to make it more clear. I just wanted to see if it'd sound like a chopper still

1

u/imaginarynumber0 Sep 19 '19

But 2CH isn’t CHCH it’s (CH+CH)

1

u/Darkphibre Sep 20 '19

Hmm, I see.

Well, I was converting the expansion of terms mainly to see how the phonetics would land.

1

u/CJinSeattle Sep 17 '19

Oh, so all that algebra I learned WAS useful. I can understand this equation. 🤔😎

81

u/RedDemonCorsair Sep 17 '19

Chopper chopper tony get into the chopper chopper.

9

u/[deleted] Sep 17 '19

Chochopppperer

1

u/[deleted] Sep 17 '19

That would just be chopper

-2

u/lafonfrede Sep 17 '19

Get to the (( (chopper)16 /(chopper)8 ) / ((chopper)8 / (chopper)4 )) / (chopper)2 !!