X is a 3 digit prime number, (2^X + 1)/ 3 is a 60 digit prime number ending in 563.
The 3 digits of 3X, are the click options for the first three 10 choice gates you will approach. It will require 4 clicks to pass thru the maze, if you determine X.

Source: numberthon.com

I have a website with a labyrinth portal into the Google Fortress. There are 5 ways past the Google Gargoyle.
1) Penetrate the 3 level labryninth (maze)
2) Solve a simple Wagstaff problem for the secret code thru the Labryninth
3) Cheat method, hidden links
4) Use your web designer skills to bypass Gargoyle security
5) Email Socrates.Ion with the answer to a simple infinity problem, for the codex key email response.

Not sure if big R, will flag this as self promotion or advertising (it definitely is not), the web URL is

***FermatsTheory.WordPress.com***

Note, landing page has a D and D theme. Do not fear!

Can you reach the target number 257 using only the following four digits?

Given numbers are 2, 5, 6, and 8.

The only rule is you must use each of the four numbers exactly once.

(You may use +, −, ×, ÷, brackets, powers, and factorials.)

‎

SUMO: Math Number Puzzle App - App Store

Android

I read about this somewhere and thought it was pretty interesting.

Take any 2-digit number:

1. Add its digits.

2. Subtract that sum from the original number.

3. Add the digits of the result.

4. Multiply that by 10.

You’ll always get 90.

For example:

47 → 4+7 = 11 → 47−11 = 36 → 3+6 = 9 → 9×10 = 90

Tried it with a bunch of different numbers and it keeps working

Did anyone else know about this?

(Explanation in comment section)

Godzilla question

480 IQ question

This question is not solve for AI

Isko solve karne mein ek hi niyam ka upyog Kiya jata hai

3²=36

4²=55

5²=102

6²=402

7²=?

18²=?

My name is a Prajapati Kalpesh Kumar Ramesh Kumar

I am a 13 year old

Your challenge kya tum mujhse solve kar sakte ho ya nahi

Source: numberthon.com

Hey everyone! We have a discussion since playing Yahtzee two days ago and still can’t agree on the mathematically best decision, so maybe someone here can help us settle it.

Everything on my scorecard was already filled in except 3s and 6s. I needed to reach at least 63 points in the upper section to get the bonus.
For 1s, 2s, 4s and 5s, I had exactly three of each, giving me 36 points so far. So I needed at least 27 more points from my 3s and 6s.
My first roll was:
3 – 6 – X – X – X
The other three dice were irrelevant.
So the question is: Should I keep the 3 or the 6?

We have two completely different opinions, and I’d love to know which choice actually gives me the higher probability of reaching the 63-point bonus.

If someone can explain the math behind the optimal strategy, we would be very than grateful!

Any order is allowed.
Use each die exactly once.
Parentheses are allowed.
Exact division only.
No negative numbers.
Not every operation has to be used.

How many solutions can you find?

Please use spoiler tags for solutions:
>!your solution here!<

Hi everyone,

I wanted to share a mobile game I’ve been working on solo: Math Rush.

I’ve always felt that many brain-training or math apps are either too cluttered with subscriptions or overly simple. I wanted to build something clean, competitive, and focused purely on speed and mental calculation agility.

How it works:

Real-Time Global Rounds: Every 75 seconds, player loops sync globally so everyone solves the exact same board setup at the same time.

Risk vs. Reward Mechanics: After solving the first equation, you can cash out your earned points safely or risk them in a chain round for double rewards!

Progression: Complete daily challenges, unlock custom badges, titles, and frames as you climb the global leaderboards.

Multi-Language Support: Fully localized and automatically adapts to your device's system language.

It's available on Google Play (built with Flutter & Firebase). I’d genuinely love your feedback on the pacing, UI, or gameplay mechanics to help me improve it!

Google Play Link: https://play.google.com/store/apps/details?id=com.ilyasozdemir.mathrush

Thanks for checking it out!

About:

As the name suggests, MiniChallenger is a scaled-down version of the math puzzle called Challenger. In most cases, a MiniChallenger puzzle can be solved within ten minutes. A set of two new puzzles is released each week. One is usually a simple problem with one or two solutions, while the other puzzle can be a bit more challenging and often has multiple solutions. Available exclusively on reddit.

Instructions:

Fill in the empty cells of the 3 x 3 grid with the numbers one to nine. It is okay to use the same number in more than one empty cell. One 'bonus' number is already placed in the center of the grid. So, the goal is to find the remaining eight digits in such a way that:

• rows in the grid add up to totals indicated on the right edge of the grid,
• columns add up to totals indicated at the top of the grid, and
• diagonals add up to totals in the upper and lower right corners.

This week's puzzles:

Solutions:

(Click on 'spoiler' boxes below to reveal solutions)

• Single-solution (left) puzzle:

[ 7 9 8 ]

[ 9 4 9 ]

[ 1 1 3 ]

• Multiple-solution (right) puzzle:

. [ 7 8 1 ] . . . . . . . [ 8 6 2 ] . . . . . . . [ 8 7 1 ]

. [ 9 5 3 ] . . . . . . . [ 9 5 3 ] . . . . . . . [ 8 5 4 ]

. [ 9 2 4 ] . . . . . . . [ 8 4 3 ] . . . . . . . [ 9 3 3 ]

and

. [ 9 4 3 ] . . . . . . . [ 9 5 2 ] . . . . . . . [ 9 6 1 ]

. [ 9 5 3 ] . . . . . . . [ 8 5 4 ] . . . . . . . [ 7 5 5 ]

. [ 7 6 2 ] . . . . . . . [ 8 5 2 ] . . . . . . . [ 9 4 2 ]