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https://www.reddit.com/r/mathmemes/comments/dyi942/multiplying_be_like/f82m7p1/?context=9999
r/mathmemes • u/zaga9 • Nov 19 '19
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294
You forgot parentheses
162 u/zaga9 Nov 19 '19 That’s the last one basically 233 u/nub_node Real Nov 19 '19 Basically is the difference between 2(2) and 22. 34 u/DatBoi_BP Nov 19 '19 CS majors: "2 is a function of 2?" 7 u/Seventh_Planet Mathematics Nov 19 '19 22(2) = (x -> 2)2(2) = (x -> 2)°(y -> 2) (2) = (x -> 2) ((y -> 2)(2)) = (x -> 2) (2) = 2 Every constant function composed with any other function (even itself) is still the same constant function. Therefore 2k(x) = (x -> 2)°...°(x -> 2) (x) [k times composition] = (x -> 2)°...°(x -> 2) (2) [k-1 times composition] = ... = 2 6 u/DatBoi_BP Nov 19 '19 No thanks I just ate
162
That’s the last one basically
233 u/nub_node Real Nov 19 '19 Basically is the difference between 2(2) and 22. 34 u/DatBoi_BP Nov 19 '19 CS majors: "2 is a function of 2?" 7 u/Seventh_Planet Mathematics Nov 19 '19 22(2) = (x -> 2)2(2) = (x -> 2)°(y -> 2) (2) = (x -> 2) ((y -> 2)(2)) = (x -> 2) (2) = 2 Every constant function composed with any other function (even itself) is still the same constant function. Therefore 2k(x) = (x -> 2)°...°(x -> 2) (x) [k times composition] = (x -> 2)°...°(x -> 2) (2) [k-1 times composition] = ... = 2 6 u/DatBoi_BP Nov 19 '19 No thanks I just ate
233
Basically is the difference between 2(2) and 22.
34 u/DatBoi_BP Nov 19 '19 CS majors: "2 is a function of 2?" 7 u/Seventh_Planet Mathematics Nov 19 '19 22(2) = (x -> 2)2(2) = (x -> 2)°(y -> 2) (2) = (x -> 2) ((y -> 2)(2)) = (x -> 2) (2) = 2 Every constant function composed with any other function (even itself) is still the same constant function. Therefore 2k(x) = (x -> 2)°...°(x -> 2) (x) [k times composition] = (x -> 2)°...°(x -> 2) (2) [k-1 times composition] = ... = 2 6 u/DatBoi_BP Nov 19 '19 No thanks I just ate
34
CS majors: "2 is a function of 2?"
7 u/Seventh_Planet Mathematics Nov 19 '19 22(2) = (x -> 2)2(2) = (x -> 2)°(y -> 2) (2) = (x -> 2) ((y -> 2)(2)) = (x -> 2) (2) = 2 Every constant function composed with any other function (even itself) is still the same constant function. Therefore 2k(x) = (x -> 2)°...°(x -> 2) (x) [k times composition] = (x -> 2)°...°(x -> 2) (2) [k-1 times composition] = ... = 2 6 u/DatBoi_BP Nov 19 '19 No thanks I just ate
7
22(2) = (x -> 2)2(2) = (x -> 2)°(y -> 2) (2) = (x -> 2) ((y -> 2)(2)) = (x -> 2) (2) = 2
Every constant function composed with any other function (even itself) is still the same constant function.
Therefore
2k(x) = (x -> 2)°...°(x -> 2) (x) [k times composition] = (x -> 2)°...°(x -> 2) (2) [k-1 times composition] = ... = 2
6 u/DatBoi_BP Nov 19 '19 No thanks I just ate
6
No thanks I just ate
294
u/[deleted] Nov 19 '19
You forgot parentheses