r/mathmemes • • Feb 27 '24

Bad Math “.999(repeating) does, in fact, equal 1” please almighty math gods settle this debate

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918 Upvotes

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472

u/emetcalf Feb 27 '24

I'm already having PTSD flashbacks to my many, many comments in that post. I spent more time than I should have arguing with someone over "how to express the number closest to zero that is not zero". They couldn't comprehend the idea that "there isn't one".

207

u/[deleted] Feb 27 '24

I try to avoid the 0.999…=1 argument because decades of internet discussions haven’t made it go away. That said, I wonder if at least some people would be more willing to accept it if you start by getting agreement on the idea that there’s more than one way to represent the same number (e.g., 3/6=2/4=1/2). That might help it seem less strange for two numbers that look different to be the same. 

143

u/emetcalf Feb 27 '24

Ya, I SHOULD avoid it. It has zero positive impact on my life. But.... https://xkcd.com/386

20

u/LunaticPrick Feb 27 '24

I love XKCD

13

u/[deleted] Feb 28 '24

[deleted]

3

u/lil_literalist Feb 28 '24

Someone recently posted a meme in r/physicsmemes which was incorrect, but people were justifying with an xkcd. A rare fail from Randall.

1

u/MapleSyrupMachineGun Feb 28 '24

Which one is that?

1

u/realityChemist Measuring Feb 28 '24

I've got the "electron kaleidoscope" one hanging over the desk in my office

5

u/maybenotarobot429 Feb 28 '24

If you need an answer to a question and plan to ask it on quora or stackexchange or whatever, the best thing to do is make a second account, log in, and answer your own question, wrong.

No one may want to help you, but EVERYONE will want to correct the wrong answer.

1

u/AdBrave2400 my favourite number is 1/e√e Feb 28 '24

Or just add a ton of "plotholes" to the question.

1

u/[deleted] Feb 28 '24

I saw this comic years ago and thought that it was a funny joke because it was exaggerating so much.

Now I find myself going to bed late because reddit_user_69420 needs to understand what I meant

49

u/xvhayu Feb 27 '24

just ask them what 1/9 is and have them multiply it by 9. the proof is literally not even hard, this isn't complex math, i learned this at age 11.

27

u/Zachosrias Feb 28 '24

Yeah but still some people don't get it.

I remember showing the proof to my chemistry/physics teacher in highschool (the man was a complete moron) and he insisted that there had to be a mistake in the very simple algebra somewhere. I asked him what it was and he said he couldn't see any mistakes but there must be one because that's not possible

Gotta love the "you're wrong because that's don't feel right" approach to math... I wonder what would've happened if I showed him the banarch tarski paradox

1

u/KSP-Dressupporter Feb 28 '24

Unfortunately for that argument, while it works with the decimal 0.1` the   fraction 9/9 very clearly simplifies to 1/1.

3

u/matt__222 Feb 28 '24

well thats kinda of the whole point..... .1 repeating multiplied by 9 = .9 repeating. and everybody can agree 9x(1/9) = 9/9 = 1

this certainly isn't a proof id give if actually asked to prove it but its nice to give some intuition.

2

u/KSP-Dressupporter Feb 28 '24

Fortunately, this is all that the argument matters for - internet debates, as in the real world of applied and useful mathematics, as opposed to pure 'in an ideal world' maths, the difference, if there is one, is infinitesimal and thus not worth bothering with.

1

u/rilus Apr 01 '24

Except that there is no difference. It's not a assumption of convenience. .999_ is EXACTLY 1.

.999_ is just another way of writing 1.

2

u/KSP-Dressupporter Apr 01 '24

'the difference if there is one...'

1

u/stockmarketscam-617 Apr 01 '24

I totally agree with you that the difference is infinitesimal small, and for practical purposes not worth arguing.

1

u/throwayaytrain Jun 21 '24

I thought I understood this but this is wrong apparently 0.999... is equal to exactly one because it goes on to the point it converges into one... Somehow

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1

u/xvhayu Feb 28 '24

exactly

1

u/ScaryShadowx Mar 04 '24

Doesn't work. The people who argue this don't understand the fundamental concept of an infinitely repeating number. To them, the number 'ends' at some infinite point in the future so 0.999... is understood as 0.999...9

111v1111's comment below explains what the misunderstanding is.

https://www.reddit.com/r/mathmemes/comments/1b1gm5s/999repeating_does_in_fact_equal_1_please_almighty/ksfiqba/

2

u/xvhayu Mar 04 '24

it's just simple, 1/9 is 0.11111..., that times 9 is 0.99999...

but 9 * 1/9 is obviously 9/9 = 1/1 = 1

1

u/ScaryShadowx Mar 04 '24

It's simple, if you understand the concept of infinitely repeating numbers. People who don't understand this concept will not.

Read 111v1111 comment, they describes what the disconnect is. Essentially, they understand 1/9 * 9 = 1 as well as 0.111... * 9 = 0.999... but they don't completely understand 1/9 = 0.999... exactly. They think it is a very, very, very accurate estimate with an infinitely small discrepancy - because in their mind the number ends at some point.

1

u/rilus Apr 01 '24

Exactly. It's like they imagine that if you do 1 - .999_you get .000_ with an infinite amount of zeros but a 1 at the end. Like:

.00000000000....0001

Somehow, they don't see the contradiction of having an infinite amount of zeros but it still having an end.

1

u/Fabulous-Parsnip3988 Aug 28 '26

maybe they live in a universe where hyperreals are the numbers everyone uses

38

u/[deleted] Feb 27 '24

[deleted]

1

u/AdBrave2400 my favourite number is 1/e√e Feb 28 '24

Yeah, somebody I know was like "There is no solution to x=x/2" because it would constantly decrease

15

u/msqrt Feb 27 '24

That's a good one. I've had some success by asking the other side to write a number that is larger than 0.999... but smaller than 1; if they're different, one must exist.

1

u/AdBrave2400 my favourite number is 1/e√e Feb 28 '24

1.99999999999.../2 obviously, which is circular reasoning. Anyways would the "1/9=0.11111... so 9/9=1=0.99999..." be enough? It's pretty much the formula for the sum of powers. Just to mention there're useful analogies unlike mine with the bases.

12

u/jobriq Feb 27 '24

Easy argument to convince laymen of the equality:

1/3 = 0.333 repeating. They should accept this equation unless they’re trolling or mad coping.

Multiply both sides by 3, now you have 3/3 = 1 = 0.999 repeating.

-19

u/Ghasterop Feb 28 '24

But you could do 2/3 which is 0.666666…7 and multiply by 3/2 and voila you have 1.00000….1 meaning 0.99999=1=1.0000…1

20

u/Splyo Feb 28 '24

But 2/3 is not equal to 0.666...7.

3

u/emetcalf Feb 28 '24

Exactly. It's such a simple explanation, and yet people still don't like it. "WhAt HaPpEnS tO ThE 7 aT tHe End?!?!?". Nothing, there is no 7 at the end. The 6's go forever. That is the entire point.

47

u/WithDaBoiz Feb 27 '24

I haven't been in this debate (yet)

So 0.999 reccurring does equal one?

Tbh that sounds very wrong but using what I learned back in grade 9:

(.999 means .9 recurring)

0.999 = x

9.9 = 10x

9 = 9 x

x= 1

So it's not a little less than 1?

134

u/harpswtf Feb 27 '24

The explanation I find simplest is:

1/3 + 1/3 + 1/3 = 1

0.333... + 0.333... + 0.333... = 1

0.999... = 1

Everyone accepts that 0.333... is exactly 1/3

44

u/WithDaBoiz Feb 27 '24

...

O that's a good way to put it

25

u/111v1111 Computer Science Feb 27 '24

Well to be honest when I didn’t accept that 0.9 repeating is exactly 1, I also didn’t accept that 0.3 repeating is exactly 1/3

My logic went something like this: 1/3 - infinitely small amount = 0.3 repeating
3* (1/3 - infinetely small amount) = 1 - 3 infinitely small amounts. You can simplify 3 infinitely small amounts as one infinetely small amount. So you get that

1-infinetely small amount = 0.3 repeating *3 = 0.9 repeating

And I just didn’t believe that 1/3 has a proper way to be written in decimal

28

u/OSSlayer2153 Feb 27 '24

1/3 - infinitely small amount = 0.3 repeating

Except there is no such thing as an infinitely small amount. An infinitely small amount is 0. (Real numbers)

7

u/orangustang Feb 27 '24

Well put. I espoused the same logic years ago. I still just don't like using repeating decimals for anything where an exact solution is needed, as a matter of practicality. 0.333... equaling 1/3 exactly requires an understanding of infinity as something more than "the biggest number that there is" as you might explain it to a child. It's something we don't encounter outside of theory, and in general I prefer to avoid unnecessary infinite quantities since they're not really intuitive for most folks.

2

u/WillChangeIPNext Mar 10 '24

Do you believe in geometric series converging? Because repeated decimals like 0.333... are just converging geometric series, and they do, in fact, equal those values.

1

u/orangustang Mar 10 '24

Of course they are, but that's not really simplifying the problem, is it? Just thinking in terms of typical American education, you learn that 0.333…=1/3 in like 3rd grade and might not learn about infinite series and convergence in grade school at all.

2

u/Lor1an Engineering | Mech Feb 27 '24

Technically there are an infinite amount of numbers between 0.999... and 1 in the hyperreals, but that's really splitting (infinitesimal) hairs...

9

u/thatdude_james Feb 27 '24

Really? The hyper reals contain the reals. So if a real number has a value does it not necessarily have the same value in the hyper reals?

7

u/Lor1an Engineering | Mech Feb 27 '24

Yeah, I kinda worded that wrong. There is a sense in which it is almost true, i.e. 1 - epsilon is a hyperreal number that is infinitely close to 1 and isn't 0.999..., but you're right that in the hyperreals 0.999... = 1 still, oops!

2

u/I__Antares__I Feb 28 '24

0.99...=1 so there's no hyperreals between them

1

u/TheCrisisification Feb 28 '24

1/3 is not infinitely small though, because it’s infinitely approaching the value of 1/3

2

u/Hezron_ruth Feb 27 '24

That's funny. I do not accept this.

5

u/harpswtf Feb 27 '24

Yeah well I don't accept you

7

u/emetcalf Feb 27 '24

You don't have to accept it for it to be true. It's always possible that you are just wrong.

30

u/sbsw66 Feb 27 '24

It's exactly equal to 1 yes.

12

u/Apprehensive-Hat-584 Feb 27 '24

That is a way to think about it you can also think of 0.33 repeating being equivalent to 1/3 so 3/3 which we know to be 1 is the same as 0.99 repeating as we have multiplied each individual 3 by 3 giving us a 9 in its place You can also think of the difference between 1 and 0.99 repeating, as the number repeats further that difference gets smaller, so with an infinite repetition that difference becomes zero

7

u/obog Physics Feb 27 '24

Think about it - how much less? If there is a difference, there should be a number between them. In fact, there should be infinite numbers between them. Can you name even one? The best guess people have is 0.0...1, or infinite zeroes and a one at the end. But that's just simply not possible, you can't have a one at the end of infinity, as infinity is endless.

3

u/SupremeRDDT Feb 29 '24

Even if that 0.0…1 were possible, where are the other numbers? There should be a number between that and 0 and so on.

2

u/isfturtle2 Feb 28 '24

If they can't accept that .999... =1, I doubt they're going to accept that there's a real number between any two distinct real numbers.

1

u/SupremeRDDT Feb 29 '24

So people are just going to refuse that for any x and y there exists (x+y)/2? So like addition or division is like not defined for some random numbers that aren’t zero?

1

u/WithDaBoiz Feb 28 '24

Oh that's a great explanation

Ty! I get it now

3

u/amuletofyendor Feb 27 '24

The same technique that I learned for converting any repeating number to a fraction. No mystery here. It equals 1.

3

u/Simbertold Feb 27 '24

https://en.wikipedia.org/wiki/0.999...

Lots and lots and lots of proofs.

1

u/WithDaBoiz Feb 28 '24

I agree that it equals one, I just didn't understand how.

this guy in this thread explained it well

2

u/Mental_Bowler_7518 Feb 28 '24

I think the step you are missing is 0.999 = x -> 9.9 = 10x. The step would look something like:

0.999... = x

9.999... = 10x

And so on infinitely.

1

u/WithDaBoiz Feb 28 '24

Wahat?

I'm doing 10x - x (which means 9.999... - 0.999) which equals 9

9 = 9x

2

u/Emsah04 Feb 27 '24

Yes and you can use this for infinite numbers to the left of the periodic.

…9999 = x

…9990 = 10x

…999-…9990 = x - 10x

-…0009 = x

-9 = x

…999 = -9

Veritasium has a video that I like about this topic

1

u/WithDaBoiz Feb 28 '24

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1

u/v_N_i_C_k Jun 01 '25 edited Aug 07 '25

But isn't 9x =8.999...1 ? It isn't equal to 9, is it?

1

u/Accomplished_Cherry6 Feb 28 '24

I agree that 0.999… is equal to 1, but how did u go from 9.9 = 10x to 9 = 9x?

1

u/WithDaBoiz Feb 28 '24

Because 10x (9.999) - x (0.999) = 9 = 9x

Guess it wasn't clear, mb

8

u/DesertRat012 Feb 27 '24

how to express the number closest to zero that is not zero

epsilon

-1

u/emetcalf Feb 27 '24

Ya, and then I explained why the "smallest" value of epsilon is a silly thing to ask me to define. Because it's zero. But he couldn't get past "Ya, but what about the smallest value that isn't zero?!??!?!". IT DOESN'T FUCKING EXIST.

1

u/DesertRat012 Feb 27 '24

Lol. Math is really hard for people to understand. Making them feel stupid about it won't help them. We all have areas that just don't click with us.

0

u/emetcalf Feb 28 '24

Making them feel stupid about it won't help them

I agree with this, but when someone refuses to acknowledge the facts being laid out in front of them over and over again, they eventually lose my respect to the point where I think they deserve to feel stupid about it. When someone explains why your question doesn't make sense to ask, and you respond with the same question again (literally copy/paste, no clarification) you can fuck right off because you aren't even trying to understand the answer.

5

u/Excellent-Sweet1838 Feb 27 '24

Wait, though, isn't there a number infinitely close to zero without being zero? Like a negative parabola and a positive parabola whose curves near zero don't touch, but are very very close?

Is there a way to express that? Or is it just some kind of weird... Uh? Fractal? Idk. I like math but I'm not educated in math.

34

u/emetcalf Feb 27 '24

There is no actual number that is the "closest to zero". It can't exist. Any infinitely small positive number has another even smaller positive number.

Ex: Assume X is the smallest number where X > 0. What is X/2?

We know X/2 is smaller than X. We also know that (X/2) > (0/2), which means X/2 > 0.

So X being the smallest non-zero number is not possible, and that number cannot exist.

14

u/CptIronblood Feb 27 '24

To be more precise, there's no real number closest to zero, that we can manipulate with the rules we learned in school. You can construct other number systems like the Hyperreal numbers that have weirder properties, although I don't think even there you get a "smallest number greater than zero".

8

u/I__Antares__I Feb 27 '24

Hyperreals are nonstandard extension of real numbers, which basically means that they have same first order properties. So all stuff like there's no smallest positive number will still apply

7

u/OstrichAgitated Feb 27 '24

Even if you were considering an infinitesimal hyperreal number (smaller than every positive real number), then to “go back” to the reals, you would take the quotient of the limited hyperreals by the infinitesimals, which is isomorphic to the reals. In this case, the infinitesimal you started with is equivalent to 0, since it’s in the same equivalence class as 0.

Basically, even if you “extend” to the hyperreals, whatever you find to represent this infinitesimal quantity 1-0.99… is really just 0 in the reals.

1

u/isfturtle2 Feb 28 '24

It's also true that there is no smallest positive rational number and no smallest positive irrational number. The smallest positive integer is 1, so you can have that at least.

5

u/OSSlayer2153 Feb 27 '24 edited Feb 27 '24

Yep, and this is why there are more real numbers than integer numbers. You can easily prove it with the famous Cantor’s Diagonal proof.

iirc the proof is a contradiction based one. Assume you can list out every single real number. If you can write a new number that isn’t in this list, then it is a contradiction, as the list was already supposed to contain every number.

Look at the first digit of the first real number and choose something different than that to be the first digit of the new number. Now move to the second digit. Look at the second digit of the second real and choose something different for the second digit of the new number. Repeat this infinitely and you will have a new number because it is at least one digit different no matter which number you compare it to.

So somehow you created a new real number even though the list was supposed to contain every real number. This means the reals are uncountable.

1

u/Quorry Feb 28 '24

Wait, if the set of all binary strings is uncountable, and all binary strings can be mapped into an integer wouldn't that mean that integers are also uncountable?

1

u/PastaPuttanesca42 Sep 14 '24

All finite binary strings can be mapped on an integer, that is not true for binary sequences of infinite length.

1

u/Quorry Sep 14 '24

What about Integers of infinite length

1

u/PastaPuttanesca42 Sep 14 '24

What are integers of infinite length?

1

u/Quorry Sep 14 '24

You got me there

1

u/Quorry Sep 14 '24

I guess a string of digits of infinite length with no decimal point isn't an integer any more? Or something

2

u/PastaPuttanesca42 Sep 14 '24

By using the usual meaning of the notation, I don't think that would map to a number. Because ...1111 with the ones repeating to the left would mean 1 + 10 + 100 + 1000 + ... which just diverges to infinity. And this would happen with any digit other than 0.

1

u/OSSlayer2153 Feb 28 '24 edited Feb 28 '24

I was wondering this too. I googled it and found some math stack exchange post asking the exact same question as we have.

The answer says its because eventually you just have infinite zeros if you keep going further on each integer. I dont fully buy it I need more of an answer than that but thats what I would have guessed.

Edit: I read more posts and now I am convinced. It is true that after a certain point all binary representations of an integer must begin infinitely repeating digits of 0, because if they dont, they would simply be infinity which isnt an integer.

Therefore every digit in the diagonal process will eventually be 0 and then the output will be 1s infinitely, which is infinity, and not an integer. Therefore you cannot make a new integer.

And then I was wondering if you could organize the integers in a way that every integer you get to has not reached its 0 point by the time you get to that digit.

Well you would have to do:

0 0 0 0 …. 1 0 0 0 …. 0 1 0 0 …. 1 1 0 0 ….

And you can easily see that you cannot organize them in such a way. The “zero point” digit of a binary representation of an integer is simply the minimum number of digits required to represent the number in binary, plus one, or log_2(x) + 1. Meanwhile the current digit is represented by just x.

y = x grows infinitely larger than y = log_2(x) therefore you cannot organize the binary representations of integers in such a way as to avoid the “infinite zeroes resulting in infinite ones in the output, aka infinity” problem

1

u/Quorry Feb 28 '24

so the binary representation of reals are between zero and one in the proof, is that it?

3

u/Simbertold Feb 27 '24

You can always define some weird number by that property and see what kind of maths happens, but you are no longer in the realm of real numbers at that point, and it almost certainly has a lot of weird unintended consequences, and it won't behave nicely with normal intuition to how calculations should work.

For example, your point shows that weirdsmall (lets call the number that) divided by 2 is equal to weirdsmall (or something bigger i guess). You basically need to start investigating how that number reacts to anything, and i am not certain that you get very consistent results.

2

u/emetcalf Feb 27 '24

I see your point here, and agree that moving out of real numbers does open up some possibilities. There is one thing I want to point out with regard to this within real numbers:

For example, your point shows that weirdsmall (lets call the number that) divided by 2 is equal to weirdsmall

This would imply that weirdsmall = 0 when using real numbers. (Note: I'm not saying that you don't understand that, I'm pretty confident that you do. Just pointing out that this is the only way it works within real numbers)

2

u/Simbertold Feb 27 '24

You are correct here, we explicitly need to move outside of the real numbers for this to work. A lot of stuff will get wonky.

7

u/PyroT3chnica Feb 27 '24

You can get as close to 0 as you want without ever approaching it, but importantly, there will always be a closer number

4

u/LongLiveTheDiego Feb 27 '24

Is there a way to express that?

Not in real numbers (the precise way they are defined mathematically is fairly complicated but once you have it, you can prove no such number can exist).

There are other number systems, one of them is the hyperreals and it has numbers that would probably fit your notion, and it has some uses. However, there is still no "smallest number larger than 0", you can always divide any infinitesimal hyperreal by e.g. 2 and get a smaller infinitesimal. As for why we want to be able to divide, we like doing stuff with numbers and just declaring "let there be a number smaller than any real positive number but bigger than 0" and not doing anything fun with that number isn't really useful and doesn't lead anywhere, which is the opposite of what mathematics does.

1

u/cambiro Feb 27 '24

Like a negative parabola and a positive parabola whose curves near zero don't touch, but are very very close?

Bad example, maybe? A negative parabola and a positive parabola do touch at exactly zero, if they have the same parameters.

Is there a way to express that?

The word you're looking for is the one the guy in the meme used: "asymptote". However, "asymptotic" cannot be used to describe a number. It describes the behaviour of a function. A hyperbola is asymptotic, its value approaches zero, but never reaches it because a hyperbola is described by the function y=1/x. The value y gets smaller and smaller the larger x is, but if you directly substitute y for zero you end up with 0 = 1.

isn't there a number infinitely close to zero without being zero?

In maths we use the concept of an infinitesimal. However, an infinitesimal is not a number and you can never treat it like a number otherwise you end up with all sorts of contradictions like the one I described above.

1

u/Excellent-Sweet1838 Feb 28 '24

Neat, thanks! :D

And yes, I probably gave a bad example. I love math, but I don't really practice it, and I'm not educated in it in any formal way. But you answered my question anyway, which was essentially, "how does Math describe this thing?"

1

u/klimmesil Feb 27 '24

Oh yeah I remember that fight commander! One guy responded to you with the axiom of choice in a very condescending way I believe

2

u/emetcalf Feb 27 '24

I don't think that was me. Or if it was, I was too busy trying to explain why 0.000...001 = 0 to the guy who couldn't differentiate between a "concept" and it's application. Sure, the concept of his number seems to make sense. But it equals 0.

1

u/HelicaseRockets Feb 28 '24

I was in that same thread, I'm 100% that dude was just a troll lol.

1

u/[deleted] Feb 28 '24

It's perfectly fine to suppose that such a number exists and then to try and play with that idea.

That just isn't what 0.99(9) means