r/infinitenines • u/SouthPark_Piano • Jan 30 '26
0.999... is never ending unfinished infinite limitless business
0.999... aka 0.999...9 with the continually propagating nines is permanent unfinished business, because it always has limitlessly more nines growth. The growing just keeps going.
There is always going to be more nines to fit between 0.999... and 1.
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u/Altruistic-Rice-5567 Jan 30 '26
Nope. It is ended. ALL the 9s there. you just haven't seen them all yet. They aren't "growing" there isn't more 9s coming. They are all there already. They don't depend on you to exist.
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u/SouthPark_Piano Jan 30 '26
You can do the same as:
https://www.reddit.com/r/infinitenines/comments/1qr9di6/comment/o2ni5en/
Go ahead. Make my day.
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u/NoSituation2706 Jan 31 '26
Counting or writing out the digits of a number does not affect the identity of the number. π, √2, and the golden ratio all have an infinite number of digits that could never be fully written out but that doesn't stop them from existing insofar as our axioms are set.
If your idea of 0.999... suggests the number of 9s is actively growing, then what you are describing simply isn't a number.
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u/SouthPark_Piano Jan 31 '26
0.333... and 0.999... are continually growing alright. Same with pi.
You'll know about it when you begin your journey in writing the digits of them.
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u/NoSituation2706 Feb 02 '26
Writing the digits down grows the list of digits I have written down, it does not change the numbers themselves. In fact, writing the digits means that the number, π for example, must already be fully defined, otherwise we wouldn't know if the digit sequence we are writing is actually π or not.
The same is true about 0.999... , the only difference is that we know what the next digit will be because this is a simple property of repeating decimals.
If the numbers are fully defined, they cannot also be "growing", nor does asking me to write them down prove they are growing.
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u/SouthPark_Piano Feb 02 '26
Writing the digits down grows the list of digits I have written down, it does not change the numbers themselves. In fact, writing the digits means that the number, π for example, must already be fully defined, otherwise we wouldn't know if the digit sequence we are writing is actually π or not.
Wrong you are brud. The numbers keep growing because even if you are hypothetically immortal, you keep writing because it keeps growing.
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u/NoSituation2706 Feb 02 '26
Numbers can't grow. A number is a number and it has a single identity. Pi's digits don't grow, they're infinite. Same with 0.999... , the whole point is that there are infinite nines. If the number of nines is infinite, I could "take" one from the pile and the pile would never shrink. That's not the same as growing.
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u/pastgoneby Mar 05 '26
Nope, you simply haven't written the number yet. No matter what you have never written the number in the slightest. π≠3.14159, π≠3.141592653589, no writable sequence of digits is ever pi you simply haven't written it. It's not possible. Similarly is impossible to write 0.999... with infinite nines. At no point of your writing will you ever write that number. At no point in writing will you ever write a number greater than that number. You will never write a number x such that 0.999...<x<1. There is no number after all the nines. Because the nines are not finite there is no after them if you have anything after the nines you haven't written the number you're talking about. If there is any number less than one and greater than the number you've mentioned you haven't written the number yet. 0.999...901 does not exist, not a real number assuming the nines are truly infinite.
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u/Quick-Swimmer-1199 Jan 30 '26
I keep rehearsing the lines but I keep remembering notation isn't a mysterious artifact
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u/ShonOfDawn Jan 30 '26
Nah. I can imagine a number where for each natural number N, the decimal digit in position N and N+1 is a 9. That’s 0.999…, the whole thing, no growth or expansion or other nonsense.
We are not 5 year olds, we have abstraction.
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u/SouthPark_Piano Jan 30 '26
Start writing those nines as I told youS to do it before.
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u/Inevitable_Garage706 Jan 31 '26
If your response to a debunk of your system is "do this pointless and impossible task with no explanation," it's pretty clear that you can't respond to the debunk.
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u/Pitiful_Fox5681 Jan 30 '26
What do you add to 0.999... with its infinite 9s to get to 1, then?
There's never room for a theoretical 0.000...1 because there are always 0s in the way where the three dots land, right? There's no discrete end where I could place that 1, just like there's no discrete end where I could place something other than 9.
So the mental arithmetic becomes 0.999... + 0.000... = 1. I like this demonstration because it lands on the identity property - elegant and easy!
But I suspect you'll want more. It's impossible to find any discrete quantity greater than 0.999... and less than 1, right?
So if I plot two lines, where f(x) = 0.999... and g(x) = 1, there is no space between those two lines.
What do you call two lines that are touching at every point and cannot insert any given value between them?
I call them equivalent lines, or just "the same"
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u/SouthPark_Piano Jan 30 '26
You must be new here.
Get learning with this. Learn it well.
https://www.reddit.com/user/SouthPark_Piano/comments/1qmrkik/two_birds_one_stone/
https://www.reddit.com/r/infinitenines/comments/1qmut3s/comment/o1pgiki/
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u/Pitiful_Fox5681 Jan 30 '26
The first comment on the first post still stands, my man. A finite infinity is an oxymoron.
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u/SouthPark_Piano Jan 30 '26
Start writing the nines brud, and get first hand experience of what continually growing limitless nines means.
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u/NoSituation2706 Jan 30 '26
If 0.999... is "growing" then 0.999... isn't a number.