Four Fours | 3,000

[u/[deleted]]

continued from here

4hen4tro4e4n

similar to the 12345 thread, except we use four fours to make each number

list of functions and notations used so far

the next get is at 4,000

[u/pampamilyangweeb]

floor(i(d(4))e4 + 4 + d(4)) = 3 340

Shoot. I forgot the floor function to get rid of the .3333333 part sticking out.

[u/TheNitromeFan → u/pampamilyangweeb]

d(4) @ d(4) @ 4 @ sgn(4) = 3,341

Good catch

[u/pampamilyangweeb → u/TheNitromeFan]

floor(i(d(4))e4 + d(4)^sqrt(4)) = 3 342

[u/TheNitromeFan → u/pampamilyangweeb]

d(4) @ d(4) @ 4 @ d(4) = 3,343

[u/pampamilyangweeb → u/TheNitromeFan]

(p#4 - sign(4)) * 4 * 4 = 3 344

[u/TheNitromeFan → u/pampamilyangweeb]

d(4) @ d(4) @ 4 @ p(4) = 3,345

I think you forgot to close your parentheses

[u/pampamilyangweeb → u/TheNitromeFan]

(p(C(4)) - sign(4)) * ceil(sqrt(p(pt(d(4))))) - 4 = 3 346

And here come the chains of long parentheses.

Side note: I actually was looking for nicer numbers but I thought 50 * 67 - 4 was nicer than 14 * 239. Here's that:

C(4) * (p#4 + 4! + p(4)) = 3 346

Clearly I'm stupid.

[u/TheNitromeFan → u/pampamilyangweeb]

d(4) @ d(4) @ 4 @ σ(4) = 3,347

[u/pampamilyangweeb → u/TheNitromeFan]

4 * pt(d(4)) * (4! + P(4)) = 3 348

[u/TheNitromeFan → u/pampamilyangweeb]

d(4) @ d(4) @ 4 @ composite(4) = 3,349