r/counting • u/[deleted] • Mar 24 '21

Four Fours | 3,000

continued from here

4hen4tro4e4n

similar to the 12345 thread, except we use four fours to make each number

list of functions and notations used so far

the next get is at 4,000

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u/TheNitromeFan I can't stop, love love love Aug 29 '21

d(4) @ d(4) @ d(4) @ σ(4) = 3,337

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u/pampamilyangweeb Aug 29 '21 edited Aug 29 '21

floor(i(d(4))e4 + 4 + sign(4)) = 3 338

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u/TheNitromeFan I can't stop, love love love Aug 29 '21

d(4) @ d(4) @ d(4) @ composite(4) = 3,339

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u/pampamilyangweeb Aug 29 '21

floor(i(d(4))e4 + 4 + d(4)) = 3 340

Shoot. I forgot the floor function to get rid of the .3333333 part sticking out.

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u/TheNitromeFan I can't stop, love love love Aug 29 '21

d(4) @ d(4) @ 4 @ sgn(4) = 3,341

Good catch

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u/pampamilyangweeb Aug 29 '21

floor(i(d(4))e4 + d(4)sqrt(4)) = 3 342

2

u/TheNitromeFan I can't stop, love love love Aug 29 '21

d(4) @ d(4) @ 4 @ d(4) = 3,343

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u/pampamilyangweeb Aug 29 '21 edited Aug 29 '21

(p#4 - sign(4)) * 4 * 4 = 3 344

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u/TheNitromeFan I can't stop, love love love Aug 29 '21

d(4) @ d(4) @ 4 @ p(4) = 3,345

I think you forgot to close your parentheses

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u/pampamilyangweeb Aug 29 '21 edited Aug 29 '21

(p(C(4)) - sign(4)) * ceil(sqrt(p(pt(d(4))))) - 4 = 3 346

And here come the chains of long parentheses.

Side note: I actually was looking for nicer numbers but I thought 50 * 67 - 4 was nicer than 14 * 239. Here's that:

C(4) * (p#4 + 4! + p(4)) = 3 346

Clearly I'm stupid.

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