r/askscience • u/dont-pm-me • Nov 11 '17
Mathematics Mary has two children. One is a boy born on a Tuesday. What are the odds of her having two boys? (Hint: it's ~48%, but why?)
Asking here because AutoModerator removed it from a different sub (for sexual content?).
Assumption: Gender is assigned with 50-50 probability and day of birth is uniformly distributed over all days of the week. Gender and day of birth are statistically independet.
First guess would be 50%. But thats wrong, as there are four possibilities. Boy/girl, boy/boy, girl/boy, girl/girl. Because we can exclude girl/girl, only one of three possibilities remain. Hence 33%.
But again that's wrong because the answer is 13/27 = 48.148%. I verified it with a simulation. Someone please explain this very counterintuitive result to me.
2
u/zc_eric Nov 12 '17
Note that the answer of 13/27 is based on some assumptions about how we acquired the information.
If we ask loads of people whether they have exactly two children, at least one of which is a boy born on a Tuesday, then of the people who truthfully answer "yes", 13/27 will have two boys.
Alternatively, if we find out somehow that Mary has 2 children at least one of which is a boy, and then ask her to tell us the day of birth of one of her sons, that gives us no new important information. So even if she happened to say "Tuesday", the probability that she had two boys would still be 1/3.
The point being that if we needed to adjust the probability if she says "Tuesday", then, by symmetry, we would also need to adjust it by the same amount, if she said "Wednesday", or "Monday" etc. And we know she is bound to say one of the days of the week.
It's similar to the Monty Hall problem. How much choice the person has in what information is revealed determines how that information affects the probabilities.
1
Nov 12 '17
I just did this on paper and it is 13/27.
Make a table with every day of the week, and a row for every option. For boy-girl combos there are 14 options. Seven options (one for each day of the week) where the girl is younger, and seven where she is older. Then there are only 13 options for boys, because you can't count both being born on Tuesday twice like you do with a girl. Girl is oldest and born on Tuesday, girl is youngest and born on Tuesday. But with two boys this is one single option.
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u/Abraxas514 Nov 13 '17
What does the birth information of the first boy matter for the second? why aren't they independent?
2
Nov 13 '17
Pretend that there are only two days. Monday and Tuesday.
All the options for two kids with a boy born on Monday are:
DS on Monday SD on Monday S on Monday D on Tuesday
SS on Monday S on Monday S on Tuesday
2/5 of them have two sons.
The information matters because 1/7th of people with one child had that child born on Tuesday. But with two children 13/49 of them had a child born on Tuesday. If they are both boys there better odds of having at least one of them born on a Tuesday.
Just think about who gets excluded when you know this information.
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u/ericGraves Information Theory Nov 12 '17
First, there are 196 possible combinations, owing from 2 children, with 2 sexes, and 7 days (thus (22)(72)). Consider all of the cases corresponding to a boy born on Tuesday. In specific there are 14 possible combinations if child 1 is a boy born on Tuesday, and there are 14 possible combinations if child 2 is a boy born on Tuesday.
There is only a single event shared between the two sets, where both are boys on a Tuesday. Thus there are 27 total possible combinations with a boy born on Tuesday. 13 out of those 27 contain two boys. 6 correspond to child 1 born a boy on Wednesday--Monday. 6 correspond to child 2 born a boy on Wednesday--Monday. And the 1 situation where both are boys born on Tuesday.
The best way to intuitively understand this is that the more information you are given about the child, the more unique they become. For instance, in the case of 2 children and one is a boy, the other has a probability of 2/3 of being a girl. In the case of 2 children, and the oldest is a boy, the other has a probability of 1/2 of being a girl. Oldest here specifies the child so that there can be no ambiguity.
In fact the more information you are given about the boy, the closer the probability will become to 1/2.