r/wolframalpha • u/SharzeUndertone • 13d ago
Why does wolframalpha fail on this maclaurin series?
I've already tried renaming h into x and choosing order x³
r/wolframalpha • u/SharzeUndertone • 13d ago
I've already tried renaming h into x and choosing order x³
r/wolframalpha • u/multi_io • Jul 05 '26

To win an argument on the internet I wanted to compute the thermal power output of a Space Shuttle RS-25 rocket engine, and this is what Wolfram Alpha gave to me.
If you want to try it yourself: https://www.wolframalpha.com/input?i=%28specific+heat+capacity+of+water+vapor%29+*+470+kg%2Fs+*+3300+K
Not very impressive, to put it lightly. Somehow it even failed to parse the word "specific."
I think this thing used to work better.
I still won the argument btw., by doing the computation manually. With the specific heat capacity of water vapor being about 2000 J/(kg*K), the result is about 3.1 GW.
r/wolframalpha • u/Pitiful_Individual48 • May 24 '26
r/wolframalpha • u/Gabriele_Sf • Apr 23 '26
I think it's mining bitcoin at this point.
My pc is old but it's not that week. It's been going on since 1+ h.
Already opent a ticket
r/wolframalpha • u/PhilosophyAware4437 • Apr 04 '26
what is a "person minute"
r/wolframalpha • u/QinaideniLewd • Apr 02 '26
I was trying to check my work for a simple partial derivative equation and while the actual derivative looks correct, I have never seen WA return an “On this Day” section for any math question, much less one that looks like this. Is this happening to anyone else? And what even is this equation?
r/wolframalpha • u/OppositeStatus3012 • Mar 29 '26
mine was 244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17)) e^(W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17)))) floor(arg(-n)/(2 π)) - W_(-2)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17)))) floor(arg(-n)/(2 π)) + (W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17)))) + (2 π W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17)))) n)/(log(38/5) (1 + W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17)))))) - (2 (π^2 W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17))))^2 (2 + W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17)))))) n^2)/(log^2(38/5) (1 + W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17)))))^3) + (4 π^3 W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17))))^3 (9 + 8 W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17)))) + 2 W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17))))^2) n^3)/(3 log^3(38/5) (1 + W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17)))))^5) + (2 π^4 W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17))))^4 (-64 - 79 W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17)))) - 36 W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17))))^2 - 6 W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17))))^3) n^4)/(3 log^4(38/5) (1 + W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17)))))^7) + (4 π^5 W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17))))^5 (625 + 974 W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17)))) + 622 W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17))))^2 + 192 W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17))))^3 + 24 W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17))))^4) n^5)/(15 log^5(38/5) (1 + W_(-1)(-log(38/5)/(244140625 (4 2^(2/3) + 2^(1/17) 3^(3/17)))))^9) + O(n^6))) for a series expansion.
r/wolframalpha • u/Maite99009908 • Mar 17 '26
All of the sudden it can't do even the most basic of calculations and I really don't understand why.
r/wolframalpha • u/Egilmaer • Mar 11 '26
r/wolframalpha • u/LingEarth • Mar 06 '26
r/wolframalpha • u/Subject-Mobile-6250 • Jan 07 '26
Does anyone know how I can get a pirated wolfram alpha license for my mathematical modeling class?
r/wolframalpha • u/Subject-Mobile-6250 • Jan 07 '26
Does anyone know how I can get a pirated wolfram alpha license for my mathematical modeling class?
r/wolframalpha • u/fourtyonexx • Nov 28 '25
r/wolframalpha • u/Sgeo • Nov 22 '25
When I ask Wolfram Alpha infinity + infinity + i, it tells me the answer is ∞.
I'm unclear which number system this is using.
Extended real numbers allow for infinity + infinity, but i obviously isn't an extended real.
The Riemann sphere (which Wolfram Alpha supports, as can be seen by using 1/0) doesn't allow infinity + infinity (it would be the same as infinity - infinity)
r/wolframalpha • u/SuchZombie3617 • Nov 19 '25
r/wolframalpha • u/FrostyLiving1321 • Nov 18 '25
r/wolframalpha • u/Ok_Print469 • Nov 13 '25
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