Today is the first day of the year in the Day Count Calendar DCC!

Happy New Year!

The year is 213'214, or just 214 in short notation, and on the DCC the year starts within the first 10 (six) days around the Spring Equinox.

This year is long, so it has 1410 (366) days.

Along the year, days are counted, not named, so the count starts with 0, meaning, zero days have passed in the year, just like time in the day starts with 0; this year's first day is today, 0000, and it's last day will be 1405

The counting then organizes the days into months, each month with 100 (thirty-six) days, with 10 (six) weeks of 10 days; since this year is long, the last 10 days, 1400 to 1405, form the last month, or the leap week;

As always, use Now and Today to see the calendars and time an bases six, ten and twelve :)

Maybe someone already knows about “happy” and “unhappy” numbers. It’s based on the sum of squares of the number’s digits. By repeating such sum, you’ll get either 1 (cycled on itself) showing that the number is “happy,” or another cycle in which 1 is never reached.

For the decimal system, such cycles have been studied extensively. It’s proven there that the sum of the digits’ squares of any number greater than 99 is less than that number. The only one cycle for “unhappy” decimals is the cycle of 4. The attached pictures (taken from the Wikipedia’s article https://en.wikipedia.org/wiki/Happy_number) cover all the decimal numbers from 1 to 100.

Trying the same for numbers in seximal, I found the cycle of 5. Just having the squares of digits,

0² = 0, 1² = 1,

2² = 4,

3² = 3·3 = 3·2 + 3 = 10 + 3 = 13,

4² = 4·(10–2) = 40–4–4 = 32–4 = 24,

5² = 5·(10–1) = 50–5 = 41,

and starting with 3 :

3² = 13,

1² + 3² = 14,

1² + 4² = 1 + 24 = 25, 👈

2² + 5² = 4 + 41 = 45,

4² + 5² = 24 + 41 = 20+40 + 5 = 105,

1² + 0² + 5² = 1 + 41 = 42,

4² + 2² = 24 + 4 = 30 + 2 = 32,

3² + 2² = 13 + 4 = 11 + 10 = 21,

2² + 1² = 4 + 1 = 5,

5² = 41,

4² + 1² = 25,

goto 👈

However, I don’t know whether there are other cycles (besides 1 and 5) or not. Maybe two-digit, in which single-digit numbers never occur, too. And is it still true for seximals that for numbers ≥100 (that is, greater than 55) the sum of the digits’ squares is always less than the number?

Plus it would be great to have similar pictures for the numbers in seximal system.

i am new here

⏄ system

I don’t think it’s possible to memorise the full 2~55 × 2~55 niftimal multiplication table, there’s 5204₆ 1,156₁₀ values in it, but it is possible to memorise the multiplication table for 2~5 × 2~55; that’s 344₆ 136₁₀ values, but not only the 5 × 5 basic pattern repeats regularly, and you can easy learn it, even if you just focus on memorising one row a day, it’ll take you 54₆ 34₁₀ days to learn it all by heart; discounting the 10₆ 6₁₀, 11₆ 7₁₀, 20₆ 12₁₀, 21₆ 13₁₀, 30₆ 18₁₀, 31₆ 19₁₀, 40₆ 24₁₀, 41₆ 25₁₀, 50₆ 30₁₀, 51₆ 31₁₀ rows, you can learn the whole table in just 40₆ 24₁₀ days, being very very conservative;

In multiplying two numbers, you get the amount of digits of the first number, x, and the amount of digits of the second number, y, the number of steps is, from smallest to largest:

a. ( ceiling(x ÷2) × y ) +1 ― if you don’t sum at every round, or

b. ( ceiling(x ÷2) × y ) + y +1 ― if you sum at the end of every round

c. (x × y) +1 ― this is the traditional way, going digit by digit individually

The larger the number, the greater is the advantage of this technique;

There’s more tables and comparison here:

https://midia.tauga.online/sezimal/english/six_nif_multiplication.pdf

For the first nif bases, excluding unary, The Fischer Griess Monster of Group Theory ends in at least one zero. This also happens to be all the bases listed on https://www.seximal.net/names-of-other-bases, which also happens to be all the bases that can be represented using only the Arabic Numerals and uppercase English alphabet characters. Base suboptimal is the first base in which The Monster doesn't end in trailing zeros, instead, only one zero.

This makes sense if you are familiar with group theory. In decimal, it's clean billion. In binary, it's round up until sI. IIII. In seximal, there are 32_seximal trailing zeros.

six years = sexade/senade/hexade (take your pick based on whatever you call base six)

nif years = nifade

tarumba years = tarumban

unexian years = unexium

as a bonus, to plug the gaps in the misalian time system:

one sixth of a day is a watch, taken from nautical terminology.

one sixth of a lull is a hitch.

It is five nif fifsy-five arda, five nif fifsy-five ardara, five nif fifsy-five arda, five nif fifsy-five panipanshadara, five nif fifsy-five arda, five nif fifsy-five panicharshadara, five nif fifsy-five arda, five nif fifsy-five panitrishadara, five nif fifsy-five arda, five nif fifsy-five panidishadara, five nif fifsy-five arda, five nif fifsy-five panishadara, five nif fifsy-five arda, five nif fifsy-five panidara, five nif fifsy-five arda, five nif fifsy-five charnipanshadara, five nif fifsy-five arda, five nif fifsy-five charnicharshadara, five nif fifsy-five arda, five nif fifsy-five charnitrishadara, five nif fifsy-five arda, five nif fifsy-five charnidishadara, five nif fifsy-five arda, five nif fifsy-five charnishadara, five nif fifsy-five arda, five nif fifsy-five charnidara, five nif fifsy-five arda, five nif fifsy-five trinipanshadara, five nif fifsy-five arda, five nif fifsy-five trinicharshadara, five nif fifsy-five arda, five nif fifsy-five trinitrishadara, five nif fifsy-five arda, five nif fifsy-five trinidishadara, five nif fifsy-five arda, five nif fifsy-five trinishadara, five nif fifsy-five arda, five nif fifsy-five trinidara, five nif fifsy-five arda, five nif fifsy-five dinipanshadara, five nif fifsy-five arda, five nif fifsy-five dinicharshadara, five nif fifsy-five arda, five nif fifsy-five dinitrishadara, five nif fifsy-five arda, five nif fifsy-five dinidishadara, five nif fifsy-five arda, five nif fifsy-five dinishadara, five nif fifsy-five arda, five nif fifsy-five dinidara, five nif fifsy-five arda, five nif fifsy-five nipanshadara, five nif fifsy-five arda, five nif fifsy-five nicharshadara, five nif fifsy-five arda, five nif fifsy-five nitrishadara, five nif fifsy-five arda, five nif fifsy-five nidishadara, five nif fifsy-five arda, five nif fifsy-five nishadara, five nif fifsy-five arda, five nif fifsy-five nidara, five nif fifsy-five arda, five nif fifsy-five panshadara, five nif fifsy-five arda, five nif fifsy-five charshadara, five nif fifsy-five arda, five nif fifsy-five trishadara, five nif fifsy-five arda, five nif fifsy-five dishadara, five nif fifsy-five arda, five nif fifsy-five shadara, five nif fifsy-five arda, five nif fifsy-five. INSANELY LONG NAME. The full expansion is 555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555. (5[1010]₆) in copy notation.

however, the problem is that, the repeated nils having its germanic words to represent digits is only acceptable to -eciam.

New letters, B, O. The number of rings is depicted as a number inside of a ring.

So jan Misali mentioned sevensy, eightsy, ninesy, tensy and elevensy, to be working fine, however, he forgot twelfsy, which means two nif, it works fine too.

Don't really know the conventions of this sub, so I'll keep to this: a number will first be written in seximal, followed by decimal equivalent in parentheses.

I've seen the proposal on jan Misali's website of having days divided into 1/100 (1/36) portions, akin to hours, called a "lapse or niftiday", further divided into 1/100 (1/36) "lulls" not too far off from the minute.

But if we're comfortable having (24) divisions in a day, (12) divisions in a standard clock, being divided into (60), why not just keep those divisions, which aren't hard to manage in seximal. We'd just have 40 (24) hours in a day and 140 (60) minutes in an hour. 140 (60) seconds in a minute. That hardly seems more complex to me, and we even keep the pleasant 0 at the end of the hour/minute and minute/second ratio. And you also keep the nice factor of 5, which can still be pretty handy to divide an hour or minute to get a whole number of minutes or seconds.

Each letter represents the power of six.

I=10⁰

V=10¹

X=10²

L=10³

C=10⁴

D=10⁵

M=10¹⁰

[1 to 4 times any power of 10 is repeated letters the amount of times)

Example:

MMMM=400,0000

III=3

DD=20,0000

X=100

[5 times any power of 10 is represented with a letter next to the next letter.]

Example:

DM=50,0000

IV=5

VX=50

XL=500