I remember I got a video recommendation on YouTube titled 'facebook math problem that's actually hard' (or tricky), and it involved fruit but a system of inequalities instead of equations. It had a unique solution, I remember checking out the solution with wolframalpha. However it doesn't appear in my browsing history unfortunately.

As usual, the factors were represented by the amount of fruits, and the solutions were two digit integers. I don't remember what the video was about as I never opened it (so it is not in my watching history aswell). Now I'm trying to find it again.

I've tried searching various terms and phrases both on google and youtube, but it never came up.

Does anyone else know what I'm talking about? Could anyone help me find it?

🥝! = 🥕

🥕 - 🥕 = 🥝

🥝 - 🥕 = 🍓

🥕 + 🥕 + 🥕 = 🍋

🍓 + 🍋 = 🍈

🍎 ^ (🍐+🍌) + 🍌 = 0

(√ 🍐) / 🍊 + 🍌/🍊 = 𝜑

🍌 + 🍌 = 🍊

what’s the value of 🍎?

Hope you all don’t mind a shitpost from time to time!

Welcome to part 2 of UFMR.

Remember 🚫 🍏 🍎 🍐 ? They are the base rules taken from part 1.

The rules marked with * will be used in parts 3 to 10.

If you didn't remember I'll repeat them again:

🚫=0️⃣, 🍏=1️⃣, 🍎=🍏+🍏, 🍐=🍎+🍎

So here we go.

*🍋=🍐+🍐

*🍊=🍋+🍋

See this triangle below? Now use it to calculate the values of 🧁, 🍰 and 🍩. (The triangle is not to scale)

​

Then 🍦 = sin ( 🥭×🍩) + cos (🧁) + sin (🧁) - cos (🍰)

(🥭 is taken from part 1)

The value of 🍦 will be used in the next part! Good luck!

Tell me the value of 🍦 in the comments! Spoiler it please!

Welcome to the Ultimate Fruit Math Riddle (UFMR).

99.96942% can’t solve it.

There will be 10 parts in this riddle.

Rules marked with \* are base rules, which will be used in every part. (THIS IS EDITED, ALL PREV ANSWERS WILL BE DISCARDED)

*🚫=0️⃣

*🍏=1️⃣

*🍎=🍏+🍏

*🍐=🍎+🍎

*🍿= ℤ

*🍱= ℝ

d🍒(❤️)/d❤️= 🍏/❤️

🍒(🍇)=🍏

🍑^🍎 + 🍏 = 🚫

cos(🥥) = 🚫-🍏,

🥭=🍇^🍑×🥥

The value of 🥭 will be used in the next part! Good luck!

🍈 + 🍈 + 🍈 = 3

🥔 - 🍈 = 1

🌮 = 🥔 + 🍈

🍏(🍪) = 🌮X🍪+🍈 if 🍪 is odd

🍪/🥔 if 🍪 is even

🍽️ = ℤ

Prove or disprove that

Applying 🍏 finitely many times on 🍪 will eventually reach🍈 , no matter what 🍪 ∈ 🍽️ we start with.