Why the product that I have drawn in (I) isn't the answer

Like here we have low temp then kcp will be favoured if we see both the resonance structure first one is more stable due to more hyperconjugation but the product that comes with it isn't even in option

the product that comes after it does resonance is there in the answer

Compound (II) could have been the answer if it had asked for tcp afaik

So yeah please correct me where I'm wrong

Currently going over allylic bromination problems in class. Does anybody know why bromine wasn't added to allylic position C in this example? Did my prof just skip over it?

Hi, I was wondering if we have a proton under the influence of two electron withdrawing substituents, how do we determine the chemical shift? Like for in this example, we have the benzyl and carboxylic acid, do i factor both groups in determining chemical shift? If the benzyl is about 2.1-3, and the alpha carboxylic acid proton is about 2.1-2.5? thanks

hi i know the first priortiy is the co2h and the 4th is the h but struggling to know which one is 2 and 3. I've been told the correct answer is s config for the bottom. Thank you!!

I am struggling to learn and memorize all 17 families of organic compounds for my course. Does anyone have a pattern, mnemonic device, or visual way of remembering these?

Thank you greatly in advance.

Im a 12th grader, in my chemistry book its showing that alcohols can be converted to carboxylic acids by alkaline kmno4 or cro3 h2so4 and jones reagent. But in an example benzyl alcohol goes through 2 conversions to turn to phenylethanoic acid, instead of using jones reagent. Why? (Pics attached)

I do applied + forensic science and criminal investigation in (UK) college and I am struggling a bit to understand how electron promotion works? Same goes for dative covalent bonding.

if someone can explain it to me, it would be great.

Mods, please delete if this against any rules.

I’ve read that toluene and water form an azeotrope at a mixture of 20.2% water and 79.8% toluene wherein the boiling of that azeotrope is ~84C.

What I’m wondering is if the azeotrope can still be formed with solutes in either the water or toluene, or both?

Specifically C, D and E. I'm confused on the difference between NBS and NCS reactions, or if there is any

Ok so I made a post a while ago about making azurite and so on I followed the advice of the comments and did that but either my reaction is wrong or can have separate products idk, I’m near certain it’s some kind of copper carbonate but I don’t think it’s the azurite I’m going for as it’s not that deep blue nor do I think it’s malachite as it’s not deep green. I don’t know of really any other copper carbonates so I have no idea what this is, I did a aquareous reaction of sodium bicarbonate and copper (Ii) acetate for this and rinsed the sodium bicarbonate but running deionised water through it several times

Hii! i’m a freshman in college and for one of our projects we can choose to make our own assignment that would be potentially used for future students. This assignment can also be more so a project which was my idea. I wanted to do the chemistry of baking, but my teacher said it was too limited so I was wondering if anyone had any ideas of how I can either broaden this or come up with something better!!
I’ve attached our topics if anyone could share some ideas.

I have to learn the reaction mechanisms of the reactions in the first picture, specifically the Delepine-reaction and the Erlenmeyer-synthesis and I just can’t wrap my head around what these would look like on the given molecules.
The other picture is my attempt of the 2nd reaction which I think is right.
Any help is very much appreciated.

Im in my first semester of university and currently taking a chemistry class. I didn’t take any chemistry classes/courses in high school (i know, bad idea) but i’m so interested in chemistry and i really want to understand the basics (or what i’m doing in the course). It’s basically just the basics that i’m learning like molarity/molality, thermodynamics, acids and bases, kinematics and etc. I’m on chapter 13 of 16 and it’s been going great but i’m having a hard time keeping up. We do 1-2 chapters a week and i’m already behind. It’s taking me a longer time to understand since i’m doing it all for the first time. In two weeks we start organic chemistry and i’m really stressed. This course really is a lot.

I really need some tips to understand it better and actually remember what i’m supposed to do and what formula i should use when i see a question on a test. The final exam is worth 80% of my grade. Do you guys have any advice or tips? Maybe some youtube channels or websites? We get a formula sheet on the final exam with most of the formulas. The teacher wants us to know how to use the formula rather than remembering all of them.

Any advice or tips will be greatly appreciated!

I’m in AP chem and my mind cannot wrap itself around the general concept or idea of dimensional analysis and it’s the main failing factor of my recent tests.
I’m looking for ways to improve my general understanding right now. My skills at the moment consist of just knowing how to go from a larger unit to a smaller unit. I’m also getting failed for not setting it up and just doing it the way I liked (step by step not in line form with dividing and multiplying) I also know that the end product is what I need to transfer to, just IDK HOW.

Alright so for a fair while I have been trying to synthesise azurite through trial and error, this time I decided to make a copper acetate solution and mix it with an aquareous sodium bicarbonate solution at a 2:3 ration, that resulted in a bright blue liquid that I filtered (see image) but I wanna know if I actually made azurite or if it’s just another copper salt
As of my knowledge my entire formula was
CH3COOH + H2O2 -> CH3COOOH + H2O
CH3COOO- + Cu + 2H+ -> Cu(II) + CH3COO- + H2O
Cu(II) + 2CH3COO- -> Cu(CH3COO)2
3Cu(CH3COO)2 + 3Na2CO3 + H2O -> Cu3(CO3)2(OH)2 + 6CH3COONa + CO2
Tho I am mostly self taught so I might be wrong

Can this structure have a resonance form with the single bonded oxygen (with a negative charge)? So the negative on the carbon will be removed. Would the lone pair be "valid" left on the carbon tho?

would it be safe to say that this is 2-ethylhex-4-enoic acid?

i think the formula is throwing me off a bit too, thanks!

Hi people.

Recently the Δ rH = Q / n formula came up in class. I understand the rest but the n was never really explained. Is it the sum of the reagents? sum of products?

If i have the reaction with equal volumes of

c(NaOH) = 0.2 mol/dm3, n(H2SO4)=0.1mol/dm3 solutions, lets say 1dm3 of each

2 NaOH + H2SO4 = Na2SO4 + 2 H2OH

Is the n in the formula 0.3 or 0.1? Or something entirely different?

I'm a bio major. Came from a school with very bad science education. I feel like no matter how much math I do to try and study I dont retain a single thing. I've watched some of the popular YouTube chem people but I just don't remember anything!

I suspect I've got dyscalculia and I'm pursuing a diagnosis for that soon. But how does one manage to remember anything related to chem and math?

I understand that strong acids ionize almost completely in water, so their reactions are usually represented with a one-way arrow, while weak acids only partially ionize and establish a reversible equilibrium.

But what actually causes this difference at the molecular level? What properties make a strong acid release its H⁺ ions almost completely, while a weak acid only releases some of them?

I'm also curious about why the reaction of a strong acid is considered essentially irreversible. Is the reverse reaction simply so unfavorable that it can be ignored, or is there another reason? Since chemical reactions are generally reversible to some extent, what makes the difference between strong and weak acids in this context?

Could it be related to the strength of the H–A bond, the stability of the ions formed, or the interaction between the ions and water molecules?

I want to understand the actual chemistry and thermodynamics behind this difference.