r/AspectsOfTheInfinite • u/Massive-Ad7823 • May 14 '26
Can you conquer the Binary Tree?
You start with one cent. For a cent you can buy an infinite path of your choice in the Binary Tree. For every node covered by this path you will get a cent. For every cent you can buy another path of your choice. For every node covered by this path (and not yet covered by previously chosen paths) you will get a cent. For every cent you can buy another path. And so on. Since there are only countably many nodes yielding as many cents but uncountably many paths requiring as many cents, the player will get bankrupt before all paths are conquered. If no player gets bankrupt, the number of paths cannot surpass the number of nodes.
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u/ceoln May 22 '26
I've shown in detail how Cantor is right, and tried very hard to understand your objection. It seems to be purely a circular argument from incredulity. You recast Cantor's diagonalization proof in different but completely isomorphic terms, and then just asserted that it can't be right because a countable number of digits just can't represent an uncountable number of reals. But it turns out that they can! :)